Using pointers write a function that receives a character string and a character as argument and deletes all occurrences of this character in the string.The function should return the corrected string wuth no holes
NO
by 
ANSWERS: 1
-
char* function(const char *str, char remove, unsigned int length) { char *newstr = new char[length+1]; memset(newstr, 0, length + 1); unsigned int innerIndex = 0; for (int i = 0; i < length; i++) { if (str[i] != remove) { newstr[innerIndex] = str[i]; innerIndex++; } } newstr[length] = '\0'; return newstr; }
-
-
mushroom The question only stated there were two arguments. I would remove the length declaration from the arguments and add: unsigned int length = strlen(str); -
brandon1234 You assume the string is properly null terminated. If it is not the function will access memory outside the proper bounds that it should which could cause unexpected Behavior. I have seen Behavior like this cause A Fault in the program causing it to crash. -
brandon1234 If you read your C api you would know that string length depends on the null terminating character. That assignment was designed very poorly and very pathetically and this is coming from a professional programmer
-
RELATED QUESTIONS
Copyright 2023, Wired Ivy, LLC