• Yes, yes they do.
  • The slope intercept form of a linear equation is: y = mx + b Where "m" is the slope and "m" can be positive, negative, zero, or undefined. Where "b" is Y-intercept and "b" can be positive, negative, zero, or non-existant. The Y-intercept does not exist, when the slope is undefined, because the line becomes a vertical line parallel to the Y axis. For example, x = 2 is a line with undefined slope and has no y-intercept. I will do an example that is similar to your line: 5x + 5y = 15 Subtract 5x from both sides of the equation: 5x + 5y - 5x = 15 - 5x simplify the left hand side: 5y = 15 - 5x divide both sides by 5 5y/5 = (15 - 5x)/5 simplify both sides: y = 3 - x swap the term on the right hand side: y = -x + 3 done! For your line 4x+4y=16, both the slope is defined and the y-intercept exists; just use algebra to rewrite the equation so that "y" is "all alone" on the left hand side of the equation, as I did in the example.

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