ANSWERS: 2

stupid 3 variable equations. 100=10x+3y+.5z 4 cows, 6 pigs, 90 sheep. owned.

Based on the comments and the process of elimination I got 5 cows, 1 pig, and 94 sheep. 5+1+94=100. (5 x $10)+(1 x $3)+(94 x $0.50) + $50 + $3 + $47 = $100 I had 2 equations: 10c + 3p + .5s = $100 c + p + s = 100 I couldn't figure out hoe the solve a system with 3 variables and only 2 equations. Anyone have any more insight on this one?
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