ANSWERS: 1
  • AB is in the plane. So is BC so b-a and c-b are in the plane. So (b-a) x (c-b) is normal to the plane. = bxc - axc -bxb + axb = bxc - axc + axb (bxb is zero) = axb + bxc - axc = axb + bxc + cxa It almost does itself.

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