ANSWERS: 1
  • 1 mole of NaOH reacts with 1 mole of KHP. Find the moles of NaOh in the reaction to get the moles of KHP, since the ratio is 1:1. NaOH required in the titration is 72.14 mL of 0.0978 mol/L. Multiply the L times mol/L to get moles. 72.14 mL = 72.14 mL / 1000 mL/L = 0.07214 L. 0.07214 L x 0.0978 mol/L = 0.007055 moles. 0.007055 moles NaOH means 0.007055 moles of KHP (if no side reactions interfere, and the titration was done properly). Assuming 0.007055 mol KHP, we convert into g using the conversion given of 204.23 g/mol KHP. 204.23 g/mol x 0.007055 mol = 1.441 g KHP. To get the percent purity, divide the amount of pure KHP by the amount of sample. 1.441 g / 1.864 g = 77.3% KHP.

Copyright 2020, Wired Ivy, LLC

Answerbag | Terms of Service | Privacy Policy