ANSWERS: 2

Ok here we go 1/(x2) +3 =16/x^2+x6 =>3x6+1/x2=16/x^2+x6 =>3x5/x2=16/x^2+3x2x6 =>3x5/x2=16/(x2)(x+3) =>3x5=16/x+3 =>3x^25x+9x15=16 =>3x^2+4x+1=0 =>3x^2+3x+x+1=0 =>(3x+1)+(x+1)=0 =>x=1/3 or x=1 Come back to me if you don't understand any step.

(1/x2)+3=(16/x^2+x6) (1/x2)+3=16/(x+3)(x2) (1/x2)+3(x2)/(x2)=16/(x+3)(x2) 1+3(x2)=16/(x+3) (1+3x6)(x+3)=16 (3x5)(x+3)=16 3x^2+4x15=16 3x^2+4x+1=0 (3x+1)(x+1)=0 x=1/3, x=1
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