ANSWERS: 2

The middle number in each row follows n^2: Row Middle number 1 1 2 (4) 3 9 4 (16) 5 25 Therefore, the middle number of the 99th row is 99^2 = 9801 The sum of the numbers in each row follows n^3: Row Sum 1 1 2 8 3 27 4 64 Therefore, the sum of row 30 is 30^3 = 27,000

I have another one for u since u'r so good at this. If all of the digits must be different, how many 3digit odd nmbers greater than 700 can be written using only the digits 1, 2, 3, 5, 6, and 7?
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