ANSWERS: 1

You mean (2x2)/(x^2x2) ? The denominator has roots at 1 and 2 The numerator has a root at x=1 There are discontinities if the denomiator has a root and the numerator does not (or if the denominator has a higher order root than the numerator). Therefore there are discontinuties at x=1 and x=2. No there is no limit. But maybe you stated the question wrong.
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